(x+1)(x^2-4)=0

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Solution for (x+1)(x^2-4)=0 equation: 


Simplifying
(x + 1)(x2 + -4) = 0

Reorder the terms:
(1 + x)(x2 + -4) = 0

Reorder the terms:
(1 + x)(-4 + x2) = 0

Multiply (1 + x) * (-4 + x2)
(1(-4 + x2) + x(-4 + x2)) = 0
((-4 * 1 + x2 * 1) + x(-4 + x2)) = 0
((-4 + 1x2) + x(-4 + x2)) = 0
(-4 + 1x2 + (-4 * x + x2 * x)) = 0
(-4 + 1x2 + (-4x + x3)) = 0

Reorder the terms:
(-4 + -4x + 1x2 + x3) = 0
(-4 + -4x + 1x2 + x3) = 0

Solving
-4 + -4x + 1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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